简体   繁体   中英

Cancel a delay if same observable emits

 const observable = new rxjs.BehaviorSubject(0); observable.subscribe(v => console.log(v)); rxjs .of(1) .pipe(rxjs.operators.delay(500)) .subscribe(v => observable.next(v)); observable.next(2); 
 <script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/6.5.1/rxjs.umd.js"></script> 

As you can see, the observable above emits 3 values in order : 0, 2, 1.

Would it be possible to cancel (or ignore) the value "1" when the value "2" is emitted ? (Without closing the subscription)

The operator you are looking for is debounceTime :

debounceTime

Emits a value from the source Observable only after a particular time span has passed without another source emission.

source

 rxjs.interval(100) .pipe( rxjs.operators.take(10), rxjs.operators.debounceTime(500) ) .subscribe((v)=>{ console.log(v); }); 
 <script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/6.5.1/rxjs.umd.js"></script> 

So for mouse enter and leave you are looking for debounceTime for example:

const observable = new BehaviorSubject(0);
observable
  .pipe(debounceTime(500))
 .subscribe(console.log);

observable.next(1),
observable.next(2);
setTimeout(() => observable.next(3) , 1000)

In this example that will print 2 and after one seconed 3. After each emitited value the observable wait for 500 ms and if there are no new value it will print in the subscribe else it will cancel the last one and start this proccess again, hope this will solve your problem

Seems like you need to switchMap from your source and apply a delay inside of it.

switchMap(value =>
 of(value).pipe(delay(50))
)

An illustration and a playground for switchMap with a delay :

使用switchMap延迟

And heres a snippet:

 const {Subject, of} = rxjs; const {switchMap, delay} = rxjs.operators; const subject = new Subject(0); subject .pipe( switchMap(value => // switchMap to a delayed value of(value).pipe(delay(500)) ) ) .subscribe(v => console.log(v)); // immediately emit 0 subject.next(0); // emit 1 in 1 sec setTimeout(()=>{ subject.next(1); }, 1000) // emit 2 in 1.2 sec setTimeout(()=>{ subject.next(2); }, 1200) 
 <script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/6.5.1/rxjs.umd.js"></script> 

Heres an example with mousehover

 const {fromEvent, merge, of, EMPTY} = rxjs; const {switchMap, delay, mapTo} = rxjs.operators; const button = document.getElementById('pane'); const mouseOver$ = fromEvent(button, 'mouseover').pipe( mapTo(true) ); const mouseOut$ = fromEvent(button, 'mouseout').pipe( mapTo(false) ); merge(mouseOver$, mouseOut$) .pipe( switchMap(value => { if (!value) { return EMPTY; } return of('mouse is over').pipe(delay(500)) }) ) .subscribe(v => console.log(v)); 
 <script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/6.5.1/rxjs.umd.js"></script> <style> #pane{ margin: 1rem; display: inline-block; width: 5rem; height: 5rem; background: rebeccapurple; }</style> <div id="pane"><div> 

Hope this helps

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM