What does | operator mean in expression-bodied property?

Question

What does | operator mean in statement looking like that:

public int IntProperty => (booTrue ? 1 : 0) | (fooTrue ? 2 : 0);

I'm familiar with => and ? but I've never seen | used like that.

Answer 1

It`sa bitwise or . If we look at the values in your code you could have:

• 0 => 00
• 1 => 01
• 2 => 10

So, if booTrue is true and fooTrue is true, it will be 1 | 2 1 | 2 . As it's a bitwise or, it will be 01 | 10 01 | 10 => 11 in decimal => 3 .