简体   繁体   中英

How to use getImagesize() for an uploaded file before it gets saved into the server?

Given that getImagesize() requires a string and $_FILES['myfile'] is an array, I've tried to get to the temporary folder and the file uploaded there in order to get the image size, but I do get an error.

This is the error that I get:

Warning: getimagesize(/home/everymorning/public_html/tmp/phpNFuAMD/images.jpeg): failed to open stream: No such file or directory in /home/everymorning/public_html/demo1.php on line 48

And here is what I've tried:

$string = $_SERVER['DOCUMENT_ROOT'].$_FILES['myfile']['tmp_name'].'/'.$_FILES['myfile']['name'];

echo getimagesize($string);

And if I try to use the temporary path directly , I still get an error:

If I use:

getimagesize($_FILES['myfile']['tmp_name']);

I get:

Notice: Array to string conversion in /home/everymorning/public_html/demo1.php on line 47

I think getimagesize($fileName) has following things-

Array ( [0] => 667 
        [1] => 184 
        [2] => 3 
        [3] => width="667" height="184" 
        [bits] => 8 
        [mime] => image/png );

You are trying to echo an array- error of Array to string conversion . Infact echo could not print array instead print_r and var_dump are the those can print the info of array.

To calculate the size of an image you can simply calculate by multiplying height width and bits used to represent a pixel and following arithmetic expression can give you size of an image in bits.

 $imageInfo = getimagesize($fileName);
 $size = $imageInfo[0] * $imageInfo[1] * $imageInfo['bits'];

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM