I know how to upload the file on the s3 bucket using boto3. But I have used it my function where I want to check like an image is successfully uploaded on the s3 bucket or not and if it is uploaded then I want to perform an action.
So here is the example like,
import boto3
def upload_image_get_url(file_name, bucket, key_name):
s3 = boto3.client("s3")
result = s3.upload_file(file_name, bucket, key_name) # Here I got none so How I will check like file is upoaded or not?
if result == 'success' or result == True:
response = "https://{0}.s3.us-east-2.amCCazonaws.com/{1}".format(bucket, key_name)
else:
response = False
return response
So my requirement is straight forward like if I got success in file upload then I will return s3 url in response. So please help me and your help will be appreciated.
The upload_file()
function does not return a value.
If there is a problem with the upload, an exception will be raised .
For example, if it cannot find the local file to upload, a FileNotFoundError
exception will be raised. (Give it a try!)
Alternatively, you can use put_object()
that will return a dict:
import os.path
import boto3
def upload_image_get_url(file_name, bucket, key_name):
s3 = boto3.client("s3")
# Get the file name
name = os.path.basename(file_name)
# Format the key
s3_key = '{0}/{1}'.format(key_name, name)
# Send the file
with open(file_name, 'rb') as fd:
result = s3.put_object(
Bucket=bucket,
Key=s3_key,
Body=fd
)
if result['ResponseMetadata']['HTTPStatusCode'] == 200:
response = "https://{0}.s3.us-east-2.amCCazonaws.com/{1}".format(bucket, s3_key)
else:
response = False
return response
The result will contains those keys:
'ResponseMetadata':
'RequestId': '...'
'HostId': '...'
'HTTPStatusCode': 200
'HTTPHeaders':
'x-amz-id-2': '...'
'x-amz-request-id': '...'
'date': 'Fri, 15 Nov 2019 10:56:15 GMT'
'x-amz-version-id': '...'
'x-amz-server-side-encryption': 'AES256'
'etag': '"..."'
'content-length': '0'
'server': 'AmazonS3'
'RetryAttempts': 0
'ETag': '"..."'
'ServerSideEncryption': 'AES256'
'VersionId': '...'
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