I am using
curl -0 https://cdn.(website).com/[range].(extension) -o "#1.(extension)"
to download files in a range of filename values.
How can I specify the range in a base higher than base 10 (I'm aiming for base 36 to encompass 0-9, az)? ex. [000-zzz]
I don't know of an easy way to print numbers in a nonstandard base in bash, but you could use bash's brace expansion to generate the range textually. You can nest brace expansions, so {{0..9},{a..z}}
will give you the digits followed by the lowercase letters. Then stack three of those to get all three-item sequences.
Note that this is a different feature from curl
's bracket and brace expansion, so you can't use it in the output filename (the #1
in your example). But you can make a shell for
loop, and use the shell variable to create the output filename. Something like this:
for itemnum in {{0..9},{a..z}}{{0..9},{a..z}}{{0..9},{a..z}}; do
curl -0 https://cdn.(website).com/${itemnum}.(extension) -o "${itemnum}.(extension)"
done
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