I need to compare two columns (a, b) of a dataframe to see how many values of "a" are greater than "b in Pandas.
I've tried this way but I don't know if it's the best option:
def result(y,z):
if(y > z):
return True
df_filtered.apply(lambda y: result(y['a'],y['b']), axis = 1)
This shows me as a result a list of true and false results, but I would need to know the amount of each.
您可以检查value_counts
df['a'].gt(df['b']).value_counts()
You need:
(df['a'] > df['b']).sum()
Consider following example:
df = pd.DataFrame({
'a':[10,20,30,40],
'b':[1,200,300,4]
})
Output:
a b
0 10 1
1 20 200
2 30 300
3 40 4
Then
(df['a'] > df['b']).sum()
Output
2
You did it right, simply add the value_counts() such that:
df_filtered.apply(lambda y: result(y['a'],y['b']), axis = 1).value_counts()
better yet, if your function result is trivial you can write:
df.apply(lambda x: x['a']>x['b'], axis=1).value_counts()
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.