How can achieve this in angular 7? how can submit this post action url in angular?
<form method="post" action="https://securegw-
stage.paytm.in/order/process" name="paytm">
<table border="1">
<tbody>
<input type="hidden" name="MID" value="YOUR_MID_HERE">
</tbody>
</table>
<script type="text/javascript">
document.paytm.submit();
</script>
</form>
Please help... thank you...
Can you try with selecting form in Component then call submit on nativeElement ?
@ViewChild('paytmForm', { read: ElementRef }) paytmForm: ElementRef;
ngAfterContentInit() {
this.paytmForm.nativeElement.submit()
}
In template add #paytmForm
on form element
<form method="post" action="https://securegw-
stage.paytm.in/order/process" name="paytm" #paytmForm >
...
</form>
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