Hello I want to know how to convert a hexadecimal array to a decimal here's my block
uint8_t block[8] = {0xb,0xb,0xb,0xa,0xa,0xa,0xa,0xa};
here's my code
#include "stdint.h"
void main() {
uint8_t block[8] = {0xb,0xb,0xb,0xa,0xa,0xa,0xa,0xa};
uint8_t key[16] = {0xa,0xa,0xa,0xb,0xb,0xb,0xb,0xb,
0xa,0xa,0xa,0xa,0xa,0xa,0xa,0xa};
UART1_Init(9600); // Initialisation de l’UART1 à 9600 bps
UART1_Write_Text("message:");
UART1_Write_Text(block);
UART1_Write_Text(" TEA Encryption:");
TEA_Enc(block, key);
UART1_Write_Text(block);
UART1_Write_Text("TEA Decryption:");
TEA_Dec(block, key);
UART1_Write_Text(block);
}
For example if i display block
i want to have as result like 123456 thank you in advance
As Eric and Eugene has said in the comments, there is no way to convert a hexidecimal number to a decimal number . Hexidecimal or decimal only exist in the code you write. Once a compiler sees a number it will store it in memory in it's own representation.
Here's an example of how you can write numbers in different representations in your code. All the numbers I write in the following code are the same. The program does not change, no matter which one you use.
int x = 0x10;
// stored in memory as:
// |0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|0|0|0|
int x = 16;
// stored in memory as:
// |0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|0|0|0|
int x = 0b00000000000000000000000000010000;
// stored in memory as:
// |0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|0|0|0|
int x = 020;
// stored in memory as:
// |0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|0|0|0|
So for your example you block
can be represented in either of these ways
uint8_t block_hex[8] = {0xb,0xb,0xb,0xa,0xa,0xa,0xa,0xa};
uint8_t block_dec[8] = {11,11,11,10,10,10,10,10};
Changing between hexidecimal and decimal will not change the behavior of your program.
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