My code:
import pandas as pd
import matplotlib.pyplot as plt
%matplotlib inline
import seaborn as sns
income_vs_hardship = %sql SELECT per_capita_income_, hardship_index FROM chicago_socioeconomic_data;
plot = sns.jointplot(x='per_capita_income_',y='hardship_index', data=pd.DataFrame(income_vs_hardship))
Correct answer:
import pandas as pd
import matplotlib.pyplot as plt
%matplotlib inline
import seaborn as sns
income_vs_hardship = %sql SELECT per_capita_income_, hardship_index FROM chicago_socioeconomic_data;
plot = sns.jointplot(x='per_capita_income_',y='hardship_index', data=income_vs_hardship.DataFrame())
The only difference:
data=pd.DataFrame(income_vs_hardship)
vs. data=income_vs_hardship.DataFrame()
If DataFrame is a method belongs to pandas, why my code does not work.
The error shows 'unable to interpret the per_capita_income.'
DataFrame
is a class of the pandas module, not a method that you can apply to a DataFrame instance.
income_vs_hardship.DataFrame()
can't be interpreted by Python, as income_vs_hardship
has no DataFrame
method. Instead, pd.DataFrame(income_vs_hardship)
creates a DtaFrame object.
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