Launch browser window with parameters using Node.js

Question

Trying develop tool using Node.js that will open new browser window with provided url and needed parameters.

Tool should work like window.open() methods.

I mean I need to hide menu bar, set size and etc.

Tried https://www.npmjs.com/package/open .

but no idea how to pass parameters like "menubar=no"

const open = require('open');

(async () => {
  await open('https://google.com', {app: ['chrome', '--incognito']});
})();

Answer 1

您需要设置标志：

--app="http://example.com" --force-app-mode

Answer 2

open.openApp(open.apps.chrome, {arguments: ['--app=https://google.com']});