简体   繁体   中英

Python Pandas: How to groupby aggregate using a function that returns pd.Series

I have a multiindexed dataframe on which I want to aggregate over some of the indices. If the aggregator function returns a float, things work with no problem. But I can't find how to use a function with more complex returns (eg, a pd.Series). Using a function that returns pd.Series gives me this error: Exception: Must produce aggregated value error.

Here is an example dataframe:

df = pd.DataFrame({
    'A': {
        (1, 0): 85, (1, 1): 75,
        (2, 0): 12, (2, 1): 15,
        (3, 0): 2,  (3, 1): 26,
    },
    'B': {
        (1, 0): 86, (1, 1): 76,
        (2, 0): 13, (2, 1): 17,
        (3, 0): 19, (3, 1): 18,
    }
}).stack()
df.index.rename(['idx', 'bar', 'label'], inplace=True)

The content of df is:

idx  bar  label
1    0    A        85
          B        86
     1    A        75
          B        76
2    0    A        12
          B        13
     1    A        15
          B        17
3    0    A         2
          B        19
     1    A        26
          B        18
dtype: int64

Let's define a simple aggregator that returns pd.Series:

def my_func(subframe):
  subframe = subframe.unstack('label')
  mean_A_plus_B = np.mean(subframe['B'] + subframe['A'])
  mean_A_minus_B = np.mean(subframe['B'] - subframe['A'])
  return pd.Series([mean_A_plus_B, mean_A_minus_B], index=['A+B', 'A-B'])
  # return mean_A_plus_B  ## <- this one works.

Applying the aggregator like the following an exception:

df.groupby('idx').agg(my_func)
.
.
.
py/pandas/core/groupby/generic.py in _aggregate_named(self, func, *args, **kwargs)
    907             output = func(group, *args, **kwargs)
    908             if isinstance(output, (Series, Index, np.ndarray)):
--> 909                 raise Exception('Must produce aggregated value')
    910             result[name] = self._try_cast(output, group)

Exception: Must produce aggregated value

What I had hoped to receive was:

       A+B    A-B
idx
1    161.0    1.0
2     28.5    1.5
3     32.5    4.5
dtype: float64

What is the right way of doing this?

Just replace .agg() by .apply() :

df.groupby('idx').apply(my_func).unstack(level=-1)

Output:

       A+B  A-B
idx            
1    161.0  1.0
2     28.5  1.5
3     32.5  4.5

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM