Suppose I have the following dataframe:
import pandas as pd
tuples = [('A', 'AA'), ('A', 'AB'), ('B', 'BA'), ('B', 'BB'),
('C', 'CA'), ('C', 'CB')]
index = pd.MultiIndex.from_tuples(tuples,
names=['first_level', 'second_level'])
input_df = pd.DataFrame([100, 500, 200, 50, 3000, 10000],
columns=['amount'], index=index)
input_df
amount
first_level second_level
A AA 100
AB 500
B BA 200
BB 50
C CA 3000
CB 10000
What I want to do is to sort based on two criteria: (1) The total amount across first_level
overall and then (2) By the amount within each second_level
.
In other words I want something like this:
tuples = [('C', 'CB'), ('C', 'CA'), ('A', 'AB'),
('A', 'AA'), ('B', 'BA'), ('B', 'BB'), ]
index = pd.MultiIndex.from_tuples(tuples,
names=['first_level', 'second_level'])
output_df = pd.DataFrame([10000, 3000, 500, 100, 200, 50],
columns=['amount'], index=index)
output_df
amount
first_level second_level
C CB 10000
CA 3000
A AB 500
AA 100
B BA 200
BB 50
As you can see group C has the largest amount (13000), followed by group A (600), and then group B (250). Within each group, the second_level is organized based on amount.
I have figured out one way of doing but it feels overly complicated as it requires aggregations, joins, and playing around with the index:
overall_group_amounts = input_df.groupby(['first_level']) \
.sum() \
.rename(columns={'amount': 'overall_amounts'})
pd.merge(overall_group_amounts, input_df.reset_index('second_level'), on='first_level') \
.sort_values(['overall_amounts', 'amount', 'first_level'], ascending=[False, False, True]) \
.drop('overall_amounts', axis='columns') \
.set_index('second_level', append=True)
My question is: is there a better way of solving this problem?
You can create a temp sort key by summing each group then sort by the key and amount at the same time:
(
df.assign(sk=df.groupby(level=0).amount.transform(sum))
.sort_values(by=['sk','amount'], ascending=False)
.drop('sk', 1)
)
amount
first_level second_level
C CB 10000
CA 3000
A AB 500
AA 100
B BA 200
BB 50
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