I'm writing a function for Firebase Cloud Functions in which I can delete old nodes from Firebase Database. On each of these nodes is a link to a file saved in Firebase Storage.
Database Structure
"data" : {
"-Lo0onTCSVeY-Kco5ujX" : {
"photo" : "https://firebasestorage.googleapis.com/v0...",
"idD" : "-Lo0onTCSVeY-Kco5ujX",
"idUs" : "jh4Ch9rBgQPwBTfv43MgNissRUP2",
"timestamp" : 1567693686925,
}
},
Function:
'use strict';
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
var DAY_MILLIS = 86400000 //1 Day
exports.deleteOldPosts = functions.database.ref('/data/{pushId}').onWrite(function(change) {
var ref = change.after.ref.parent; // reference to the parent
var now = Date.now();
var cutoff = now - DAY_MILLIS;
var oldItemsQuery = ref.orderByChild('timestamp').endAt(cutoff);
return oldItemsQuery.once('value').then(function(snapshot) {
// create a map with all children that need to be removed
var updates = {};
snapshot.forEach(function(child) {
updates[child.key] = null;
});
// execute all updates in one go and return the result to end the function
return ref.update(updates);
});
});
How can I do to delete the file too? Thanks in advance.
This works for me
const promises = [];
promises.push(ref.update(updates));
const bucket = admin.storage().bucket();
promises.push(bucket.file(`file/${anotherFile}`).delete());
return Promise.all(promises);
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