How to convert string “2019-10-09T06:07:05.888Z” as calendar date and time

Question

Please help me to find a solution for converting "2019-10-09T06:07:05.888Z" as a calendar time stamp. I tried the following methods,

> format(as.POSIXlt("2019-10-09T06:07:05.888Z"), "%Y-%m-%d %H:%M:%OS3")
[1] "2019-10-09 00:00:00.000"

> as.POSIXct("2019-10-09T06:07:05.888Z", format="%Y-%m-%d %H:%M:%OS")
[1] NA

Answer 1

With as.POSIXct , we can first convert the data into POSIXct class and then use format to display the output in the format we want.

temp <- as.POSIXct("2019-10-09T06:07:05.888Z",format = "%Y-%m-%dT%H:%M:%OS", tz = "UTC")
format(temp, "%Y-%m-%d %H:%M:%OS3")
#[1] "2019-10-09 06:07:05.888"

Or with lubridate

format(lubridate::ymd_hms("2019-10-09T06:07:05.888Z"), "%Y-%m-%d %H:%M:%OS3")

Answer 2

Simply add options(digits.secs = 3) above as.POSIXct() for getting the exact calendar format.

> options(digits.secs = 3)
> as.POSIXct("2019-10-09T06:07:05.888Z",format = "%Y-%m-%dT%H:%M:%OS", tz = "UTC")
[1] "2019-10-09 06:07:05.888 UTC"