is there a way of running celery worker in debug mode; much like flask debug?

Question

• I find myself having to manually restart celery worker whenever I make a change to the task source code
• Is there a faster way of coding/debugging celery tasks?
• Something similar to how flask can be run in DEBUG=1 mode; where changes in the HTML and routes are automatically reloaded
• I am currently running celery worker in a docker container with the following command:

celery worker -l info -A celery_tasks.app -n celery_worker -B

Answer 1

There is nothing built in but you can use the watchmedo utility from watchdog which monitors a directory for file changes and allows you to restart your worker.

You just need to install it with pip :

pip install watchdog[watchmedo]

And run:

watchmedo auto-restart --directory=./ --pattern="*.py" --recursive -- celery worker -l info -A celery_tasks.app -n celery_worker -B