So I have a pandas data frame of lenght 90 which isn't important Lets say I have :
df
A date
1 2012-01-01
4 2012-02-01
5 2012-03-01
7 2012-04-01
8 2012-05-01
9 2012-06-01
2 2012-07-01
1 2012-08-01
3 2012-09-01
2 2012-10-01
5 2012-11-01
9 2012-12-01
0 2013-01-01
6 2013-02-01
and I have created a new data frame
df_copy=df.copy()
index = range(0,3)
df1 = pd.DataFrame(index=index, columns=range((len(df_copy.columns))))
df1.columns = df_copy.columns
df1['date'] = pd.date_range('2019-11-01','2020-01-01' , freq='MS')-pd.offsets.MonthBegin(1)
which should create a data frame like this
A date
na 2019-10-01
na 2019-11-01
na 2019-12-01
So I use the following code to get the values of A in my new data frame
df1['A'] = df1['A'].iloc[9:12]
And I want the outcome to be this
A date
2 2019-10-01
5 2019-11-01
9 2019-12-01
so I want that the last 3 values are assigned the value that has iloc position 9-12 in the new data frame, the indexes are different and so are the dates in both data frames. Is there a way to do this because
df1['A'] = df1['A'].iloc[9:12]
doesn't seem to work
According to my knowledge you can solve this by genearting several new data frames
df_copy=df.copy()
index = range(0,1)
df1 = pd.DataFrame(index=index, columns=range((len(df_copy.columns))))
df1.columns = df_copy.columns
df1['date'] = pd.date_range('2019-11-01','2019-11-01' , freq='MS')-pd.offsets.MonthBegin(1)
df1['A'] = df1['A'].iloc[9]
Then appending to your original data frame and repeating it is a bit overwhemling but it seems like the only solution i could came up with
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