I already read similar posts as mine, but they didn't help.
So what is happening is I am following kudvenkat's asp.net core mvc tutorial series.
I have a simple form with some fields that work perfectly fine, and they are sending data normally, but the field for Photo upload does not work. Whenever I hit Submit button, a field of an object ( model.Photo ) that should hold file name in HomeController is null . It might has something with changes made from 2.1 to 3.0 version of asp.net core, but I am only guessing.
Create.cshtml (I pasted only code of that field and submit button, form method is set to POST)
<div class="form-group">
<label asp-for="Photo"></label>
<div class="custom-file">
<input asp-for="Photo" class="form-control custom-file-input" formenctype="multipart/form-data"/>
<label class="custom-file-label">Choose file...</label>
</div>
</div>
<div>
<button class="btn btn-secondary" type="submit"><i class="fas fa-plus-square"></i> Create</button>
</div>
HomeController.cs (I pasted only code of intrest for this problem, I can show the rest of code if you ask for)
public IActionResult Create(EmployeeCreateViewModel model)
{
if(ModelState.IsValid)
{
string uniqueFileName = null;
if(model.Photo != null)
{
string uploadsFolder = Path.Combine(hostingEnviroment.WebRootPath, "img");
uniqueFileName = Guid.NewGuid().ToString() + "_" + Path.GetFileName(model.Photo.FileName);
string filePath = Path.Combine(uploadsFolder, uniqueFileName);
model.Photo.CopyTo(new FileStream(filePath, FileMode.Create));
}
Employee newEmployee = new Employee
{
FirstName = model.FirstName,
LastName = model.LastName,
Email = model.Email,
Department = model.Department,
Job = model.Job,
Address = model.Address,
Birthday = model.Birthday,
PhotoPath = uniqueFileName
};
_employeeRepository.Add(newEmployee);
return RedirectToAction("Details", new { id = newEmployee.Id });
}
return View();
}
EmployeeCreateViewModel.cs
public class EmployeeCreateViewModel
{
[Required]
[Display(Name = "First name")]
public string FirstName { get; set; }
[Required]
[Display(Name = "Last name")]
public string LastName { get; set; }
[Required]
[RegularExpression(@"^[a-zA-Z0-9_.+-]+@coreuniverse.com",
ErrorMessage = "Invalid email format. Follow pattern: etc@coreuniverse.com")]
public string Email { get; set; }
[Required]
public Dept? Department { get; set; }
[Required]
public string Job { get; set; }
[Required]
public string Birthday { get; set; }
[Required]
public string Address { get; set; }
public IFormFile Photo { get; set; }
}
This picture shows a breakpoint when Create() action is triggered. It proves that the value is NULL
I assume that you're facing with the error at :
if(model.Photo != null)
{
string uploadsFolder = Path.Combine(hostingEnviroment.WebRootPath, "img");
uniqueFileName = Guid.NewGuid().ToString() + "_" + Path.GetFileName(model.Photo.FileName);
string filePath = Path.Combine(uploadsFolder, uniqueFileName);
model.Photo.CopyTo(new FileStream(filePath, FileMode.Create));
}
First of all could you please try to change your input field as following:
<input asp-for="Photo" type='file' value='@Model.Photo' class="form-control custom-file-input" formenctype="multipart/form-data"/>
Added type='file'
& value='@Model.Photo'
Now you should send type of IFormFile
value to your action.
Ensure that your form must contain enctype="multipart/form-data"
as follows:
<form method="post" enctype="multipart/form-data">
<div class="form-group">
<label asp-for="Photo"></label>
<div class="custom-file">
<input asp-for="Photo" class="form-control custom-file-input"/>
<label class="custom-file-label">Choose file...</label>
</div>
</div>
<input type="submit" value="Upload Image" name="submit">
</form>
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.