Suppose we have the query :
EightWeekGamePlan.aggregate(
[
{
$group: {
_id: {
LeadId: "$LeadId",
Week: "$Week",
InsertDate: "$InsertDate" , // I want to group by the date part
Status: "$Status"
},
count: { $count: 1 }
}
},
{
$lookup: {
from: "leads",
localField: "_id",
foreignField: "LeadId",
as: "Joined"
}
},
{ $unwind: "$Joined" },
{ $replaceRoot: { newRoot: { $mergeObjects: ["$Joined", "$$ROOT"] } } },
{ $sort: { total: -1 } }
],
function(err, results) {
if (err) {
console.log(err);
}
// ... do some manipulations ...
console.log(_filtered);
return res.json(_filtered);
}
);
I grouping by multiple fields and I want to take only the date part of InsertDate
and disregard the time.
How can we do that ?
I believe your question is addressed in mongodb documentations under Group by Day of the Year :
https://docs.mongodb.com/manual/reference/operator/aggregation/group/
You have to convert the date into date-formatted string using $dateToString
and add it to $group _id
_id : {$dateToString: { format: "%Y-%m-%d", date: "$InserDate" }}
I hope this helps!
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