I've copied the W3 schools code for performing a mysqli row count function, but when I input my variables, the returned result is always '1'. I have checked my SQL code by entering it directly into phpMyAdmin, which returns the correct result.
This is my code:
<?php
$con = mysqli_connect("x", "x", "x", "x");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT COUNT(*) FROM `Existing_Bookings`";
if ($result=mysqli_query($con,$sql))
{
// Return the number of rows in result set
$rowcount=mysqli_num_rows($result);
printf("Result set has %d rows.\n",$rowcount);
// Free result set
mysqli_free_result($result);
}
mysqli_close($con);
?>
I just wondered if anyone can see any obvious reason behind this? My server is running PHP 5.6 which is why I have ensured I am using mysqli, rather than mysql for this.
If you have any rows in the table, selecting count(*)
will always return just one row (as you've seen). The content of the row contains the actual count you've queried:
$sql="SELECT COUNT(*) FROM `Existing_Bookings`";
if ($result = mysqli_query($con,$sql)) {
// Return the number of rows in result set
$row = mysqli_fetch_array($result, MYSQLI_NUM);
printf("Table has %d rows.\n", $row[0]);
// Free result set
mysqli_free_result($result);
}
mysqli_close($con);
Your query is counting the number of Bookings which will always return 1 row that includes the count. mysqli_num_rows will provide you with a row count so in this case it will always be 1.
Quick Fix: change sql to SELECT * FROM Existing_Bookings
Better Fix: check the check to read the row: $row = mysqli_fetch_row($result)
and then $row[0] will contain the count.
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