I have the following dataframe where words took the place of default row numbers (1,2,3, etc.):
Score
commitment -0.9843452
progress -0.9831530
implement -0.9785868
decision -0.9777243
message -0.9762919
deficit -0.9752300
invest 0.9929340
multiplier 0.9940889
fiscal_capacity 0.9940889
public_investment 0.9949193
aggregate_demand 0.9955452
space 0.9960338
I want to achieve two things: 1) the "column" of words to become a proper column (the second column of the dataframe); 2) keep only those words that have a score bigger or equal 0. I tried a lot of solution but I failed. Unfortunately, I don't know how to create a dfm with words instead of numbers so I can't provide you with code (I derived it from list in my real-life scenario).
Is there anyone who can help me with that? Thanks so much!
Here is an option with base R
. Create a data.frame
from the row names of the dataset and subset
the rows based on the values of 'Score'
subset(data.frame(newcol = row.names(df1), Score = df1$Score), Score >=0)
Or using tidyverse
library(dplyr)
library(tibble)
rownames_to_column(df1, 'newcol') %>%
filter(Score >= 0)
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