I'm trying desperately with ForEach to only display what has the value true. No matter what I try, false is also displayed. The air is out now and I think it's so simple that I just don't see it. Here is a piece of code to which it should apply:
import SwiftUI
struct txt: Identifiable {
var id: Int
var text: String
var show: Bool
}
struct ContentView: View {
@State private var array = [
txt(id: 000, text: "True", show: true),
txt(id: 001, text: "True", show: true),
txt(id: 002, text: "True", show: true),
txt(id: 003, text: "False", show: false),
]
var body: some View {
NavigationView {
List {
ForEach(array.indices, id: \.self) { idx in
Text("\(self.array[idx].text)")
}
}
}
}
}
Change your ForEach
like this:
ForEach(array) { arr in
if arr.show {
Text("\(arr.text)")
}
}
List(array.filter { $0.show }){ (item) in
Text(item.text)
}
UPDATE:
let ids = [0,2]
let filteredItems = array.filter { ids.contains($0.id)}
gives you filtered collection with two items only where Element.id == 0 or Element.id == 2
array.filter { $0.show } is collection of three items , where Element.show == true
you can use it as source of data
List(array.filter { ids.contains($0.id) }){ (item) in
Text(item.text)
}
and it will produce one Text for each of its source collection
both conditions (or more) could be applied with any logical operators, as you want
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