dataHAVE = data.frame("student"=c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),
"time"=c(1,2,3,1,2,3,1,2,3,NA,NA,NA,NA,2,3),
"score"=c(7,9,5,NA,NA,NA,NA,3,9,NA,NA,NA,7,NA,5))
dataWANT=data.frame("student"=c(1,1,1,3,3,3,5,5,5),
"time"=c(1,2,3,1,2,3,NA,2,3),
"score"=c(7,9,5,NA,3,9,7,NA,5))
I have a tall dataframe and in that data frame I want to remove student IDS that contain NA for all 'score' or for all 'time'. This is just if it is all NA, if there are some NA then I want to keep all their records...
Is this what you want?
library(dplyr)
dataHAVE %>%
group_by(student) %>%
filter(!all(is.na(score)))
student time score
<dbl> <dbl> <dbl>
1 1 1 7
2 1 2 9
3 1 3 5
4 3 1 NA
5 3 2 3
6 3 3 9
7 5 NA 7
8 5 2 NA
9 5 3 5
Each student
is only kept if not ( !
) all
score
values are NA
Since nobody suggested one, here is a solution using data.table
:
library(data.table)
dataHAVE = data.table("student"=c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),
"time"=c(1,2,3,1,2,3,1,2,3,NA,NA,NA,NA,2,3),
"score"=c(7,9,5,NA,NA,NA,NA,3,9,NA,NA,NA,7,NA,5))
Previous but wrong code:
dataHAVE[, .SD[!(all(is.na(time)) & all(is.na(score)))], by = student]
New and correct code:
dataHAVE[, .SD[!(all(is.na(time)) | all(is.na(score)))], by = student]
Returns:
student time score
1: 1 1 7
2: 1 2 9
3: 1 3 5
4: 3 1 NA
5: 3 2 3
6: 3 3 9
7: 5 NA 7
8: 5 2 NA
9: 5 3 5
Updatet data.table
solution with @Cole s suggestion...
Here is a base R solution using subset
+ ave
dataWANT <- subset(dataHAVE,!(ave(time,student,FUN = function(v) all(is.na(v))) | ave(score,student,FUN = function(v) all(is.na(v)))))
or
dataWANT <- subset(dataHAVE,
!Reduce(`|`,Map(function(x) ave(get(x),student,FUN = function(v) all(is.na(v))), c("time","score"))))
Another option:
library(data.table)
setDT(dataHAVE, key="student")
dataHAVE[!student %in% dataHAVE[, if(any(colSums(is.na(.SD))==.N)) student, student]$V1]
Create a dummy variable, and filter based on that
library("dplyr")
dataHAVE = data.frame("student"=c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),
"time"=c(1,2,3,1,2,3,1,2,3,NA,NA,NA,NA,2,3),
"score"=c(7,9,5,NA,NA,NA,NA,3,9,NA,NA,NA,7,NA,5))
dataHAVE %>%
mutate(check=is.na(time)&is.na(score)) %>%
filter(check == FALSE) %>%
select(-check)
#> student time score
#> 1 1 1 7
#> 2 1 2 9
#> 3 1 3 5
#> 4 2 1 NA
#> 5 2 2 NA
#> 6 2 3 NA
#> 7 3 1 NA
#> 8 3 2 3
#> 9 3 3 9
#> 10 5 NA 7
#> 11 5 2 NA
#> 12 5 3 5
Created on 2020-02-21 by the reprex package (v0.3.0)
data.table
solution generalising to any number of columns:
dataHAVE[,
.SD[do.call("+", lapply(.SD, function(x) any(!is.na(x)))) == ncol(.SD)],
by = student]
# student time score
# 1: 1 1 7
# 2: 1 2 9
# 3: 1 3 5
# 4: 3 1 NA
# 5: 3 2 3
# 6: 3 3 9
# 7: 5 NA 7
# 8: 5 2 NA
# 9: 5 3 5
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