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How to copy a 16 bit number from 16 bit register to a variable which has the length of 32 bit in 8086?

原文 2020-03-03 16:05:47 3 1 assembly/ x86-16/ emu8086

I want to copy a 16 bit number from a register to a 32 bit long variable. How can I do this in 8086?

1 answers

I want to copy a 16 bit number from a register to a 32 bit long variable. How can I do this in 8086?

Assembler 8086 divide 32 bit number in 16 bit number

Reading in 16 bits from a 32 bit register

Assembly 8086 ,range of a 16 bit register and cmp

Toggle nibbles in a 16 bit register (8086)

How do I copy values from an 8-bit array to a 16-bit array in 8086 assembly?

manipulating 32 bit numbers with 16 bit registers in 8086

how can i split a string containing a 32bit number into two 16bit register

EMU8086 dividing 32 bit number by a 16 bit number gives unexpected 0 remainder

How to convert 64 bit function to 32 bit to 16 bit to 8 bit?

Pushing a 32 bit register onto a '16 bit stack'

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Related Question Assembler 8086 divide 32 bit number in 16 bit number Reading in 16 bits from a 32 bit register Assembly 8086 ,range of a 16 bit register and cmp Toggle nibbles in a 16 bit register (8086) How do I copy values from an 8-bit array to a 16-bit array in 8086 assembly? manipulating 32 bit numbers with 16 bit registers in 8086 how can i split a string containing a 32bit number into two 16bit register EMU8086 dividing 32 bit number by a 16 bit number gives unexpected 0 remainder How to convert 64 bit function to 32 bit to 16 bit to 8 bit? Pushing a 32 bit register onto a '16 bit stack'

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How to copy a 16 bit number from 16 bit register to a variable which has the length of 32 bit in 8086?

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1 answers

solution1 -1 2020-04-09 03:42:43

solution1
-1 2020-04-09 03:42:43