简体   繁体   中英

Get unique count of column values in VBA based on filtering another column

I have an excel sheet where there are 7 columns. I need to get unique count of users(in column A) based on filtering column C(Active - A, Inactive - I). Example

User_ID  Status
A1        A
A2        I
A1        A
A3        I
A2        I

Currently, I am using below code to get total count of the column but I need to first filter Status=A, then get unique count of column User_ID if any duplicates are there in column A. I searched on the internet but was not able to find any proper solution, I am very new to VBA so kindly help.

DSheet.Range("A2").End(xlDown).Row

Use

Collection

Private Sub Test()
Dim Test As New Collection
Dim Test1 As New Collection
Dim rng As Range
For i = 2 To 6 'replace 6 with last row number
    Value = Cells(i, "A").Value
    check = Contains(Test, Value)
    check1 = Contains(Test1, Value)
    If Cells(i, "B").Value = "A" And Not check And Len(Value) > 0 Then
        MsgBox Value
        Test.Add Value, CStr(Value)
    ElseIf Cells(i, "B").Value = "I" And Not check1 And Len(Value) > 0 Then
        Test1.Add Value, CStr(Value)
    End If
Next i
On Error GoTo 0
MsgBox Test.count ' Distinct count for Status A
MsgBox Test1.count ' Distinct count for Status I
End Sub

'Function to check if the value exists in collection.
Public Function Contains(col As Collection, key As Variant) As Boolean
Dim obj As Variant
On Error GoTo err
    Contains = True
    obj = col(key)
    Exit Function
err:

    Contains = False
End Function

Thank you so much for your help. I was able to execute through shorter code. I am filtering one column and getting unique counts based on filtered values. Sharing the code:

SSheet.Range("$A:$S").Autofilter field:=2, Criteria1:="A"
Set List=CreateObject(Scripting.Dictionary)

For Each ids In SSheet.Range("A2:A" & LastRow).SpecialCells(xlCellTypeVisible)
 If Not List.Exists(ids.Value) Then List.Add ids.Value, Nothing
Next
MsgBox List.count

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM