Kotlin: Higher-order function with Suspend Function return type

Question

How to return suspend function from regular function? How to create suspend function instance?

For example, I can return async result from function:

fun <T> f(g: () -> T): Deferred<T> = GlobalScope.async { g() }

But I notices Kotlin allow the following signature of function:

fun <T> f(g: () -> T): suspend () -> T {
    TODO()
}

How can I implement it?

Answer 1

@Rene 的回答但更短：

fun <T> f(g: () -> T) = suspend { g() }

Answer 2

One way to do it:

fun <T> f(g: () -> T): suspend () -> T {
    suspend fun intern() = g()
    return ::intern
}