javascript return statement to stop executing the rest of statements

Question

I have scenario where I want to break the next function call if the previous function has return statement but I can see it is executing next function call even after I have return statement in below function named "b".

function main(){
  a()
  b();
  c();
}

function a(){
  console.log("function a call!!");
}
function b(){
  console.log("function b call!!");
  return function(){return 0;}
}
function c(){
  console.log("function c call!!");
}

main()

Outout :

'function a call!!'
'function b call!!'
'function c call!!'

Expected output:

'function a call!!'
'function b call!!'

Can someone can explain me what is right way to do here?

Answer 1

You cannot do control flow on a caller function from a callee function. your code just returns a function from b() , but that function is never executed, and even if it is, it won't have the expected behavior. If you want to interrupt main , have to do it in main itself:

function main(){
  a()
  const bReturnValue = b();
  if(bReturnValue <some condition>) {
      return;
  }
  c();
}

function a(){
  console.log("function a call!!");
}
function b(){
  console.log("function b call!!");
  return function(){return 0;}
}
function c(){
  console.log("function c call!!");
}

main()

Answer 2

You can't cancel the function call of C since you don't check for what b returns. Let b return true for example, and check with

let resultB = b();
if(!resultB) c();