package main
import (
"fmt"
"time"
)
func main() {
c := make(chan int)
go func() {
fmt.Println("hello")
c <- 10
}()
time.Sleep(2 * time.Second)
}
In the above program, I have created a Go routine which is writing to channel c but there is no other go routine which is reading from the channel. Why isnt there a deadlock in this case?
A deadlock implies all goroutines being blocked, not just one arbitrary goroutine of your choosing.
The main
goroutine is simply in a sleep, once that is over, it can continue to run.
If you switch the sleep
with a select{}
blocking forever operation, you'll get your deadlock:
c := make(chan int)
go func() {
fmt.Println("hello")
c <- 10
}()
select {}
Try it on the Go Playground .
See related: Why there is no error that receiver is blocked?
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