PHP Display Shell Command Output in a box in Real Time
Question
I have the following code which asks for input then applies shell.sh $folderPath $bits $group2
And I would like to have a box where it displays the output of my script exactly how it would've looked if I ran in in a terminal.
How do I do that?
Below is my code.
<?php
if (isset($_GET['folderPath']) && !empty($_GET['folderPath']) && file_exists($_GET['folderPath'])
&& is_dir($_GET['folderPath']) && isset($_GET['bits']) && isset($_GET['group2'])) {
$folderPath = $_GET['folderPath'];
$bits = $_GET['bits'];
$group2 = $_GET['group2'];
$run = shell_exec("shell.sh $folderPath $bits $group2");
echo "shell.sh $folderPath $bits $group2";
var_dump($run);
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title></title>
</head>
<body>
<form action="">
<label for="folderPath">Folder Path:</label>
<input type="text" id="folderPath" name="folderPath">
<br></br>
<fieldset id="bits">
<p>Please Choose bits: </p>
<input type="radio" value="8bits" name="bits"> 8bits <br>
<input type="radio" value="16bits" name="bits"> 16bits <br>
</fieldset>
<br></br>
<fieldset id="audio-type">
<p>Please Choose Type: </p>
<input type="radio" value="C12" name="group2"> C12 <br>
<input type="radio" value="LR" name="group2"> LR <br>
</fieldset>
<input class = "submitButton" type="submit" value="Submit">
</body>
</html>
1 answers
solution1
0 2020-05-07 17:52:25
First of all, you need to send your form data somewhere. In your case, it is your same script.
<form method="GET" action="path/to/my/script.php">
Secondly, shell_exec() returns output of executed command. You already wrote the code.
$path = $_GET['folderPath'];
$bits = $_GET['bits'];
$group2 = $_GET['group2'];
$output = shell_exec("shell.sh $path $bits $group2");
Thirdly, display the output where you want.
<div><?php print $output; ?></div>
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.