I would like to count how often one variable id_tasks occurs per month. The month variable is from 1 to 12.
So far i have only managed to count how often, each task occurs with the help of: I would like to know how often the task occurs in every month as the output, in order to detect which month has the most/least tasks.
count(df,c('id_task'))
id_task id_user day completion_yesno day_created has_deadline deadline created_before active overdue completed_before month
16416 37033 5272 61 0 61 1 172 0 0 0 0
16417 37033 5272 62 0 61 1 172 2 2 0 0
16418 37033 5272 63 0 61 1 172 2 2 0 0
16419 37033 5272 64 0 61 1 172 2 2 0 0
16420 37033 5272 65 0 61 1 172 2 2 0 0
16421 37033 5272 66 0 61 1 172 2 2 0 0
16422 37033 5272 67 0 61 1 172 2 2 0 0
16423 37033 5272 68 0 61 1 172 2 2 0 0
16424 37033 5272 69 0 61 1 172 2 2 0 0
16425 37033 5272 70 0 61 1 172 2 2 0 0
16426 37033 5272 71 0 61 1 172 2 2 0 0
16427 37033 5272 72 0 61 1 172 2 2 0 0
16428 37033 5272 73 0 61 1 172 2 2 0 0
16429 37033 5272 74 0 61 1 172 2 2 0 0
16430 37033 5272 75 0 61 1 172 2 2 0 0
16431 37033 5272 76 0 61 1 172 2 2 0 0
16432 37033 5272 77 0 61 1 172 2 2 0 0
16433 37033 5272 78 0 61 1 172 2 2 0 0
16434 37033 5272 79 0 61 1 172 2 2 0 0
16435 37033 5272 80 0 61 1 172 2 2 0 0
desired output:
id_task month freq
1 12 3
2 1 20
if you want to count the occuriencies of all the month X task combinations, table
is your function:
table(df[, c("month", "id_task")])
You can rerun this with this dummy data:
df <- data.frame(id_task= sample.int(15, 100, replace = TRUE), month = rep(1:12, length.out=100))
table(df[, c("month", "id_task")])
If you want the sum of tasks per month just drop the task column and run it like this:
table(df[, c("month")])
You can ask with the dplyr package the following:
data %>%
> group_by(month) %>%
> count(id_task)
I think this will do. (:
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