I've two Spark DataFrames. Where df1
contains addresses and df2
streetnames, cities, regions etc.
df1 = spark.createDataFrame([
["001", "Luc Krier","2363 Ryan Road, Long Lake South Dakota","2363RyanRoad,LongLakeSouthDakota"],
["002", "Jeanny Thorn","2263 Patton Lane Raleigh North Carolina","2263PattonLaneRaleighNorthCarolina"],
["003", "Teddy E Beecher","2839 Hartland Avenue Fond Du Lac Wisconsin","2839HartlandAvenueFondDuLacWisconsin"],
["004", "Philippe Schauss","1 Im Oberdorf Allemagne","1ImOberdorfAllemagne"],
["005", "Meindert I Tholen","Hagedoornweg 138 Amsterdam","Hagedoornweg138Amsterdam"]
]).toDF("id","name","address1", "address2")
df2 = spark.createDataFrame([
["US","Amsterdam"],
["US","SouthDakota"],
["LU","Allemagne"],
["FR","Allemagne"],
["NL","Amsterdam"],
["NL","Rotterdam"],
["US","Wisconsin"],
["AU","Wisconsin"],
["AU","Hartland"]
]).toDF("cc","point")
I want to check if df1['address2'] contains any of the values from df2['point'] and the expected result is (fictitious and not in accordance with the dataframe examples) a new column cc
with values like:
('US':1)
('US':2)('NL':1)
('US':3)('FR':1)('LU':1)
('NL':1)
returns cc
from df2['cc']
and the number of matches. An address can hit on multiple values from df2
. Sorted by number of matches (highest first)
You can perform a "conditional" join. Bet be aware, like @Steven mentioned in his comment, this will create a cross-join. Performance wise this will not be your best option. But just know that what you try to achieve is possible when you don't take performance into account.
df_join = df1.join(df2, df1.address2.contains(df2.point), how='left')
result = df_join
.groupBy('id','name','address1', 'cc').count()
.select('id', 'name', 'address1', f.concat(f.lit("'"), f.col("cc"), f.lit("':"), f.col("count")).alias('cc'))
.groupBy('id','name','address1').agg(f.concat_ws("", f.collect_list(f.col("cc"))).alias('cc'))
What may help is that you broadcast df2 (the smallest one).
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