简体   繁体   中英

How Can I Run a Streamlit App from within a Python Script?

Is there a way to run the command streamlit run APP_NAME.py from within a python script, that might look something like:

import streamlit
streamlit.run("APP_NAME.py")


As the project I'm working on needs to be cross-platform (and packaged), I can't safely rely on a call to os.system(...) or subprocess .

Hopefully this works for others: I looked into the actual streamlit file in my python/conda bin, and it had these lines:

import re
import sys
from streamlit.cli import main

if __name__ == '__main__':
    sys.argv[0] = re.sub(r'(-script\.pyw|\.exe)?$', '', sys.argv[0])
    sys.exit(main())

From here, you can see that running streamlit run APP_NAME.py on the command line is the same (in python) as:

import sys
from streamlit import cli as stcli

if __name__ == '__main__':
    sys.argv = ["streamlit", "run", "APP_NAME.py"]
    sys.exit(stcli.main())

So I put that in another script, and then run that script to run the original app from python, and it seemed to work. I'm not sure how cross-platform this answer is though, as it still relies somewhat on command line args.

You can run your script from python as python my_script.py :

import sys
from streamlit import cli as stcli
import streamlit
    
def main():
# Your streamlit code

if __name__ == '__main__':
    if streamlit._is_running_with_streamlit:
        main()
    else:
        sys.argv = ["streamlit", "run", sys.argv[0]]
        sys.exit(stcli.main())

I prefer working with subprocess and it makes executing many scripts via another python script very easy.

The subprocess module allows you to spawn new processes, connect to their input/output/error pipes, and obtain their return codes. This module intends to replace several older modules and functions:

    import subprocess
    import os
    process = subprocess.Popen(["streamlit", "run", os.path.join(
        'application', 'main', 'services', 'streamlit_app.py')])

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM