I don't understand what this error means. I am trying to declare an Array that contains arrays of two numbers. For instance,
[[1, 2], [4, 3], [5, 6]]
These are the type signatures I'm using.
const knightTour = (start: number[], size: number): void => {
const [i, j] = start;
let path: number[][] = [];
const queue: Array<[number[]]> = [start];
}
However, I'm getting the aforementioned error when I try to initialise my queue variable. What am I doing wrong?
The complete error message is:
(parameter) start: number[] Property '0' is missing in type 'number[]' but required in type '[number[]]'.(2741)
and it reveals where the error is.
const queue: Array<[number[]]> = [start];
The type of queue
is array of [number[]]
(array of arrays of arrays of numbers) and you want tot initialize it with an array of arrays of numbers.
I suspect the type of queue
is incorrect and it should be Array<number[]>
.
To add to @axiac's answer:
The type:
[number[]]
is a Tuple type which matches arrays of size one, whose only element has type of number[]
.
So valid values for that type would be:
[[1, 2, 3]]
[[77, 33]]
[[]]
etc. It is obvious that [number[]]
is not a useful type. I would think that a tuple type makes sense if there are at least two elements in a tuple. For example this type:
[string, number, number[]]
could be used to store a string, a number and an array of numbers (if an application has a need for such a record).
['one', 1, [1]]
['six', 6, [1, 2, 3, 6]]
['ten', 10, [1, 2, 5, 10]]
In your case it's obvious that it's just a simple error. The intention seems to be that queue
should be an array of arrays. So the type of queue
can be just:
number[][]
and its definition and initialization:
const queue: number[][] = [start];
or just:
const queue = [start];
and let TypeScript infer the number[][]
type.
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