if __name__ == __main__ not working after compilation

Question

i'm actually working on a script using multiprocessing library, everything is working perfectly from my text editor ( VSC ):

import multiprocessing

def example_func():
    print("This is a targeted function for multiprocessing")
    
if __name__ == "__main__":
    print("This is the main session, starting multiprocessing")
    multiprocessing.Process(target=example_func).start()

so in my text editor when i run the code it output this :

This is the main session, starting multiprocessing
This is a targeted function for multiprocessing

but after I compile it to .exe using pyinstaller, something very strange happens, the code starts getting looped infinitely, its like if after i compiled it, the processes were considered as the main session, it means that in if __name__ == "__main__" processes were considered as main .

Please guys help, i really need your help.

EDIT : some guys told me to add string, I have already had it as a string in my script.I just didnt copy well here

Answer 1

You need to use multiprocessing.freeze_support appropriately when you're freezing to a Windows executable:

if __name__ == "__main__":
    multiprocessing.freeze_support()  # Required for PyInstaller
    print("This is the main session, starting multiprocessing")
    multiprocessing.Process(target=example_func).start()

Without it, the Windows "fork-like" behavior multiprocessing relies on doesn't know where to stop executing code when it launches subprocesses with the same executable.

Answer 2

It is a string:

if __name__ == "__main__":
    pass

Note the double quotes instead of __main__ as an object (?).

Answer 3

我真的不知道为什么它没有在那里抛出错误，但__main__应该是一个字符串'__main__'

Answer 4

You have to compare __name__ to string __main__

import multiprocessing

def example_func():
    print("This is a targeted function for multiprocessing")
    
if __name__ == "__main__":
    print("This is the main session, starting multiprocessing")
    multiprocessing.Process(target=example_func).start()