Rust pipeline operator for Any by overloading operators

Question

Composition operator and pipe forward operator in Rust

use std::ops::Shr;

struct Wrapped<T>(T);

impl<A, B, F> Shr<F> for Wrapped<A>
where
    F: FnOnce(A) -> B,
{
    type Output = Wrapped<B>;

    fn shr(self, f: F) -> Wrapped<B> {
        Wrapped(f(self.0))
    }
}

fn main() {
    let string = Wrapped(1) >> (|x| x + 1) >> (|x| 2 * x) >> (|x: i32| x.to_string());
    println!("{}", string.0);
}
// prints `4`

Here's a code of pipeline operator for struct: Wrapped by overloading an operator, but I need one that can be used for native values that I think as &dyn Any .

Since I don't understand type system of Rust yet, so I did like

use std::any::Any;

impl<A, B, F: Fn(A) -> B> Shr<F> for &dyn Any {
    type Output = &dyn Any;

    fn shr(self, f: F) -> &dyn Any {
        f(self.0)
    }
}

but with obvious errors.

How can I sort this out? Thanks.

Answer 1

Thanks to @mcarton,

Rust pipeline operator for Any by overloading operators

I found a similar solution:

https://docs.rs/apply/0.3.0/apply/trait.Apply.html

pub trait Apply<Res> {
    /// Apply a function which takes the parameter by value.
    fn apply<F: FnOnce(Self) -> Res>(self, f: F) -> Res
    where
        Self: Sized,
    {
        f(self)
    }

    /// Apply a function which takes the parameter by reference.
    fn apply_ref<F: FnOnce(&Self) -> Res>(&self, f: F) -> Res {
        f(self)
    }

    /// Apply a function which takes the parameter by mutable reference.
    fn apply_mut<F: FnOnce(&mut Self) -> Res>(&mut self, f: F) -> Res {
        f(self)
    }
}

impl<T: ?Sized, Res> Apply<Res> for T {
    // use default definitions...
}

fn main() {
    let string = 1
        .apply(|x| x * 2)
        .apply(|x| x + 1)
        .apply(|x: i32| x.to_string());
    println!("{}", string);
}