I need to open UIViewController from SwiftUI with UINavigation having back button.
Currently, I had implemented this via ViewControllerRepresentable and NavigationLink, its works, but I have two Navigations SwiftUI(NavigationLink with back button) and default UINavigation without back button, and I would like to perform to have my default UINavigation with the back button and hide SwiftUI(NavigationLink) navigation.
struct UIKitVc : UIViewControllerRepresentable {
let navigationController = UINavigationController()
func updateUIViewController(_ uiViewController: UINavigationController, context: Context) {
}
func makeUIViewController(context: Context) -> UINavigationController {
let storyboard = UIStoryboard(name: "Main", bundle: nil)
let viewController = storyboard.instantiateViewController(withIdentifier: "SearchResult") as! SearchResultViewController
self.navigationController.addChild(viewController)
return self.navigationController
}
}
NavigationLink(destination: UIKitVc(){}
Thank you in advance.
If you're going to use NavigationView/NavigationLink
then you don't need to use UINavigationController
, just use representable over your UIViewController
, like
struct UIKitVc : UIViewControllerRepresentable {
func updateUIViewController(_ uiViewController: UIViewController, context: Context) {
}
func makeUIViewController(context: Context) -> UIViewController {
let storyboard = UIStoryboard(name: "Main", bundle: nil)
let viewController = storyboard.instantiateViewController(withIdentifier:
"SearchResult") as! SearchResultViewController
// ... make additional set up here if needed
return viewController
}
}
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