(Absolute beginner here)
The following code should replace every 9th row of the template df with EVERY row of the data df. However it replaces every 9th row of template with every 9th row of data.
template.iloc[::9, 2] = data['Question (en)']
template.iloc[::9, 3] = data['Correct Answer']
template.iloc[::9, 4] = data['Incorrect Answer 1']
template.iloc[::9, 5] = data['Incorrect Answer 2']
Thank you for your help
The source of the problem with your code is that the initial step to any operation on 2 DataFrames is their alignment by indices.
To avoid this step, take the underlying Numpy array from one of arrays, invoking values . Since Numpy array has no index, Pandas can't perform the mentioned alignment.
Another correction is:
To create both source test arrays, I defined the following function:
def getTestDf(nRows : int, tt : str, valShift=0):
qn = np.array(list(map(lambda i: tt + str(i),np.arange(nRows, dtype=int))))
ans = np.arange(nRows * 3, dtype=int).reshape((-1, 3)) + valShift
return pd.concat([pd.DataFrame({'Question (en)' : qn}), pd.DataFrame(ans,
columns=['Correct Answer', 'Incorrect Answer 1', 'Incorrect Answer 2'])], axis=1)
and called it:
template = getTestDf(80, 'Question_')
data = getTestDf(9, 'New question ', 1000)
Note that after I created template I counted that just 9 rows in data are needed, so I created data with just 9 rows.
This way the initial part of template contains:
Question (en) Correct Answer Incorrect Answer 1 Incorrect Answer 2
0 Question_0 0 1 2
1 Question_1 3 4 5
2 Question_2 6 7 8
3 Question_3 9 10 11
4 Question_4 12 13 14
...
and data (in full):
Question (en) Correct Answer Incorrect Answer 1 Incorrect Answer 2
0 New question 0 1000 1001 1002
1 New question 1 1003 1004 1005
2 New question 2 1006 1007 1008
3 New question 3 1009 1010 1011
4 New question 4 1012 1013 1014
5 New question 5 1015 1016 1017
6 New question 6 1018 1019 1020
7 New question 7 1021 1022 1023
8 New question 8 1024 1025 1026
Now, to copy selected rows, run just:
template.iloc[::9] = data.values
The initial part of template contains now:
Question (en) Correct Answer Incorrect Answer 1 Incorrect Answer 2
0 New question 0 1000 1001 1002
1 Question_1 3 4 5
2 Question_2 6 7 8
3 Question_3 9 10 11
4 Question_4 12 13 14
5 Question_5 15 16 17
6 Question_6 18 19 20
7 Question_7 21 22 23
8 Question_8 24 25 26
9 New question 1 1003 1004 1005
10 Question_10 30 31 32
11 Question_11 33 34 35
12 Question_12 36 37 38
13 Question_13 39 40 41
14 Question_14 42 43 44
15 Question_15 45 46 47
16 Question_16 48 49 50
17 Question_17 51 52 53
18 New question 2 1006 1007 1008
19 Question_19 57 58 59
I am pretty sure that there are simpler/nicer ways, but just off the top of my head:
template_9=template.iloc[::9,0:2].copy()
# outer join
template_9['key'] = 0
data['key'] = 0
template_9.merge(data, how='left') # you don't need left here, but I think it's clearer
template_9.drop('key', axis=1, inplace=True)
template = pd.concat([template,template_9]).drop_duplicates(keep='last')
In case you want to keep the index replace:
template_9.reset_index().merge(data, how='left').set_index('index')
and then you can sort by index in the end.
PS I'm assuming column names are the same in both data frames, but it should be straightforward to adapt it anyway.
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