I use typescript generics in my project but it seems not work well.
example:
interface Test<T, P> {
a?: (v: T) => P
b?: (v: P) => void
}
const fn1 = <T, P>(_config: Test<T, P>) => {}
fn1({
a: (p) => 1,
b: (p) => {},
})
I think params 'a'
type just like:
Test<unknown, number>.a?: ((v: unknown) => number) | undefined
But, actually:
Test<unknown, unknown>.a?: ((v: unknown) => unknown) | undefined
I do not know why, someone can help me? Thanks.
Since you are not defining the type on this line: b: (p) => {}
Then TS cannot infer the type of P, even though you return it in the above definition for a
.
This is because in a union an unknown absorbs everything.
For P in (a) TypeScript infers a type of "number", but then for P in (b) it infers a type of "unknown", just as it does for T in (a).
Therefore, P results in a "number | unknown" (not "number | undefined" as you expected), which results in just "unknown".
If you refer to the TypeScript docs here , you'll find:
// In a union an unknown absorbs everything
type P = unknown | number; // unknown
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