Given the integer 'number' in the range of 0..<< 1000, print the number as a word. For example, given: let number: Int = 125 output should be one-hundred and twenty-five
You can use NumberFormatter pretty effectively:) Here's example
let numberFormatter = NumberFormatter()
let number = 12355532
numberFormatter.numberStyle = .spellOut
let numberAsWord = numberFormatter.string(from: NSNumber(value: number))
print(numberAsWord)
You could also extend NSNumber to do this behind the scenes like this
public extension NSNumber {
var spelledOut: String? {
let formatter = NumberFormatter()
formatter.numberStyle = .spellOut
return formatter.string(from: self)
}
}
To avoid creating a Number Formatter every time you call this property you can create a static formatter. You can also make the computed property generic to support all numeric types:
extension NumberFormatter {
static let spelled: NumberFormatter = {
let formatter = NumberFormatter()
formatter.numberStyle = .spellOut
return formatter
}()
}
extension Numeric {
var spelledOut: String? { NumberFormatter.spelled.string(for: self) }
}
let integer = 1234
let integerSpelled = integer.spelledOut // "one thousand two hundred thirty-four"
let double = 123.4
let doubleSpelled = double.spelledOut // "one hundred twenty-three point four"
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