I have the following table:
.table tbody tr:nth-child(4n+1), .table tbody tr:nth-child(4n+2) { background: rgb(247, 247, 247); }
<div class="container"> <table class="table table-sm"> <thead class="thead-default"> <tr> <td>Column 1</td><td>Column 2</td> </tr> </thead> <tbody> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> <tr> <td>Column Data</td><td>Column Data</td> </tr> </tbody> </table> </div>
I can change the background colour of the nth row with CSS by doing:
.table tbody tr:nth-child(4n+1),
.table tbody tr:nth-child(4n+2) {
background: rgb(247, 247, 247);
}
How can I do the same by changing the style of the table inline? I have tried to replace
<table class="table table-sm">
with
<table style="tr:nth-child(4n+1){background: rgb(247, 247, 247)}; tr:nth-child(4n+2){background: rgb(247, 247, 247)}" class="table table-sm">
but it does not work. I am a bit confused about the correct syntax.
An inline style relates only to the element in whose tag it is written (ie without a selector). You'd have to write the background definition into each single td
to which it should apply...
As an in-between solution (between external stylesheet and inline style), you can add a <style>
tag to your HTML code and put the CSS rules in there.
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