I have a dataframe:
import pandas as pd
df = pd.DataFrame({
'ID': ['ABC', 'ABC', 'ABC', 'XYZ', 'XYZ', 'XYZ'],
'value': [100, 120, 130, 200, 190, 210],
'value2': [2100, 2120, 2130, 2200, 2190, 2210],
'state': ['init','mid', 'final', 'init', 'mid', 'final'],
})
I want to create dictionary of unique values of the Column 'ID'. I can extract the unique values by:
df.ID.unique()
But that gives me a list. I want the output to be a dictionary, which looks like this:
dict = {0:'ABC', 1: 'XYZ'}
If the number of unique entries in the column is n, then the keys should start at 0 and go till n-1. The values should be the names of unique entries in the column
The actual dataframe has 1000s of rows and is often updated. So I cannot maintain the dict manually.
Try this. -
dict(enumerate(df.ID.unique()))
{0: 'ABC', 1: 'XYZ'}
If you want to get unique values for a particular column in dict, try:
val_dict = {idx:value for idx , value in enumerate(df["ID"].unique())}
Output while printing val_dict
{0: 'ABC', 1: 'XYZ'}
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