My current code is this:
$('.how-we-menu').on('click', function() {
$('.how-we-menu > ul').slideDown();
$('.under').on('click', function() {
$('.under > ul').slideDown();
})
$('.over').on('click', function() {
$('.over > ul').slideDown();
})
$('.ar').on('click', function() {
$('.ar > ul').slideDown();
})
$('.fc').on('click', function() {
$(this).children('ul').slideToggle();
})
});
I am trying to avoid slide toggle because it affects another element and slides both of them up so I want to make each element work individually. So when you click ".fc > ul" once it slides down and when you click again it slides up.
I hope this makes sense thanks!
Use $(this)
in the function so it only affects the element you clicked on.
$('.fc').on('click', function() {
$(this).children('ul').slideToggle();
});
And all the event handlers should be at top level, not inside another event handler. Since they all do the same thing, you can bind them all at once.
$('.how-we-menu, .under, .over, .ar, .fc').on('click', function() { $(this).children('ul').slideToggle(); });
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.