I am changing an API created in a flask to FastAPI, but I don't know how to change this code, any advice:
@app.route('/download/<fname>', methods=['GET'])
def download(fname):
return send_file(fname)
Thanks in advance.
It all depends of what kind of file you're trying to download. But you can find good information here: FastApi Streaming Response
In your case it would be something like:
from fastapi.responses import StreamingResponse
@app.get("/download")
async def download(fname : str):
file_like = open(fname, mode="rb")
return StreamingResponse(file_like, media_type="type of your file")
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