How to prevent right mouse button click onMouseDown() react js?

Question

I am using onMouseDown and onMouseUp for better control. I already have onContextMenu but how I can prevent the right button click on onMouseDown and onMouseUp .I only want the left button to be clicked.

because currently 2 events triggering at the same time. My context menu and other function open at the same time.

Answer 1

You can check if e.button === 2 or not. When you right click then the value of e.button is 2 .

Though i'm not sure about it's browser support.

You can check this example.

 const {useState} = React; const App = () => { const [value, setValue] = useState('left or right click'); const handleMouseDown = (e) => { if(e.button === 2) return; console.log('handleMouseDown'); } const handleMouseUp = (e) => { if(e.button === 2) return; console.log('handleMouseUp'); } const handleContextMenu = (e) => { console.log('handleContextMenu'); } return ( <div className="test" onMouseDown={handleMouseDown} onMouseUp={handleMouseUp} onContextMenu={handleContextMenu} >{value}</div> ); }; // Render it ReactDOM.render( <App/>, document.getElementById("react") );

 .test { width: 100vw; height: 100vh; text-align: center; font-size: 20px; }

 <script src="https://cdnjs.cloudflare.com/ajax/libs/react/17.0.1/umd/react.production.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/17.0.1/umd/react-dom.production.min.js"></script> <div id="react"></div>

Answer 2

onMouseDown={(event) => {
 if (event.button === 0) { ***write some code***}
}}

event.button === 0 left , event.button === 1 middle , event.button === 2 right ,