This is what the sample looks like:
start_location_Long start_location_Lat end_location_Long end_location_Lat start_time1_cos end_time1_cos clusterNum
[1,] 0.52378920 2.4368453 0.54442969 2.4795016 -0.8556297 -0.9205550 6
[2,] 0.52067466 2.4344570 -0.19032110 1.0495159 0.9838412 3.4135479 5
[3,] 0.15442785 1.9243047 0.22881591 1.6337213 -0.0616968 -0.8731549 6
[4,] 0.40289891 0.5148578 0.46360470 1.2610018 -0.3169268 -0.2686603 6
[5,] 0.04622642 1.0748470 0.12649364 1.0431320 -0.7774222 -0.7788368 6
[6,] 0.63314416 0.9234254 0.14450812 1.0302006 -0.8225888 -0.8123482 6
[7,] 0.68966729 0.6019531 1.21697046 0.9342789 -0.7434470 0.4569955 4
[8,] 2.32099405 0.9297944 2.14687817 -0.6940977 -0.8340856 -0.6665446 4
[9,] 0.06549043 -0.5369730 0.07749424 -0.5310636 -0.3612566 -0.4558744 8
[10,] -0.32832583 0.0215832 -0.23823963 -0.3066462 0.8659375 1.0576191 7
out <- structure(c(0.523789201116763, 0.520674661270142, 0.154427845973528,0.402898913736964, 0.0462264246354297, 0.633144155731261, 0.68966728628088,2.3209940459422, 0.0654904303534412, -0.328325830252011, 2.43684534992552,2.43445699655717, 1.92430471707559, 0.514857782627747, 1.07484703572908,0.923425432175079, 0.601953068793905, 0.929794374490717, -0.536973040797758,0.0215832002825539, 0.544429688416353, -0.190321103194908, 0.228815912614685,0.463604699407898, 0.126493638268144, 0.144508123188246, 1.21697045877012,2.14687817035007, 0.0774942392852146, -0.238239633082625, 2.4795015924936,1.04951586212972, 1.63372134194528, 1.26100184697751, 1.04313199726203,1.03020057868387, 0.93427891682567, -0.694097690965059, -0.53106360357468,-0.306646200148732, -0.855629693492673, 0.983841170626353, -0.0616968018017336,-0.316926796024306, -0.777422178678194, -0.82258880499052, -0.743446969246078,-0.834085583349327, -0.361256556045013, 0.865937517514796, -0.920554961834621,3.41354789197562, -0.873154942000389, -0.268660340896956, -0.778836788633205,-0.812348178573314, 0.456995511946368, -0.666544551696315, -0.455874395664872,1.05761911141203, 6, 5, 6, 6, 6, 6, 4, 4, 8, 7), .Dim = c(10L,7L), .Dimnames = list(NULL, c("start_location_Long", "start_location_Lat","end_location_Long", "end_location_Lat", "start_time1_cos", "end_time1_cos","clusterNum")))
So, I want to convert this large matrix to a data frame because I want to export this data into CSV format later on.
My expected result should look like this;
start_location_Long start_location_Lat end_location_Long end_location_Lat start_time1_cos end_time1_cos clusterNum
<dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
0.52378920 2.4368453 0.54442969 2.4795016 -0.8556297 -0.9205550 6
0.52067466 2.4344570 -0.19032110 1.0495159 0.9838412 3.4135479 5
0.15442785 1.9243047 0.22881591 1.6337213 -0.0616968 -0.8731549 6
0.40289891 0.5148578 0.46360470 1.2610018 -0.3169268 -0.2686603 6
0.04622642 1.0748470 0.12649364 1.0431320 -0.7774222 -0.7788368 6
0.63314416 0.9234254 0.14450812 1.0302006 -0.8225888 -0.8123482 6
0.68966729 0.6019531 1.21697046 0.9342789 -0.7434470 0.4569955 4
2.32099405 0.9297944 2.14687817 -0.6940977 -0.8340856 -0.6665446 4
0.06549043 -0.5369730 0.07749424 -0.5310636 -0.3612566 -0.4558744 8
-0.32832583 0.0215832 -0.23823963 -0.3066462 0.8659375 1.0576191 7
Thank you in advance.
The expected output is a tibble
. So, we can use as_tibble
library(tibble)
out1 <- as_tibble(out)
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