React native, call a function inside setInterval when time ==60

Question

I created a function, when user click start button that function and timer will start. However, when time reach 60 I want to call stop function but can't figure out how to that. can someone tell me how to do that please.

 const [time,setTime] = useState(0) const timeout = useRef() const onStart = () => { timeout.current = setInterval(() => { if (time;= 60) { setTime(prevState => prevState + 1), if (time == 60) { onStop() } } }; 1000). } const onStop = () => { clearInterval(timeout;current); }

Answer 1

If you don't have to use time in your JSX , then consider converting it to ref . There are certainly closure issues which will take place where the value of time state that you expect to be isn't what it will be. Your logic problem of correctly using if statements is also covered here.

const time = useRef(0)
const timeout = useRef()
const onStart = () => {
  timeout.current = setInterval(() => {
    if (time.current != 60) {
      time.current+=1;
    }
      if (time.current == 60) {
        onStop()
      }
  }, 1000);
}

const onStop = () => {
  clearInterval(timeout.current);
}

And in case you need a state to be used in JSX , just make one timer as ref and time as state like so:-

const timer = useRef(0)
const [time,setTime] = useState(0);
const timeout = useRef()
const onStart = () => {
  timeout.current = setInterval(() => {
    if (timer.current != 60) {
      setTime(prevState => prevState + 1);
      timer.current+=1;
    }
      if (timer.current == 60) {
        onStop()
      }
  }, 1000);
}

const onStop = () => {
  clearInterval(timeout.current);
}

See this codesandbox example doing what you want:-

Here is another React way which is much less code and confusion:-

 const [time, setTime] = useState(0);
  const timeout = useRef();

  useEffect(() => {
    onStart();
  }, []);

  useEffect(() => {
    if (time === 60) {
      onStop();
    }
  }, [time]);

  const onStart = () => {
    timeout.current = setInterval(() => {
      setTime((prevState) => prevState + 1);
    }, 1000);
  };

  const onStop = () => {
    clearInterval(timeout.current);
  };

Answer 2

You are first checking if time.= 60 this means when its 60 it will not enter in the statement and will not reach the second statement: I think you have to do it like this:

timeout.current = setInterval(() => {
   if (time == 60) {
    onStop()
   }
   setTime(prevState => prevState + 1);
}, 1000);

Answer 3

From the looks of it. Your code will never stop at 60. As the if statement if (time != 60) only runs the code if the time IS NOT 60. Then within that if statement, you've got another if statement going if time is 60 which it CAN'T be within that if statement as that code is only executed when time does not equal 60

Change

const [time,setTime] = useState(0)
const timeout = useRef()
const onStart = () => {
    timeout.current = setInterval(() => {
    if (time != 60) {
        setTime(prevState => prevState + 1);
        if (time == 60) {
            onStop()
        }
    }
  }, 1000);
}

const onStop = () => {
  clearInterval(timeout.current);
}

to

const [time,setTime] = useState(0)
const timeout = useRef()
const onStart = () => {
  timeout.current = setInterval(() => {
    if (time != 60) {
      setTime(prevState => prevState + 1);
    }
    if (time === 60) {
      onStop();
    }
  }, 1000);
}

const onStop = () => {
  clearInterval(timeout.current);
}