I want to start a single mongod instance with command mongod --config config/mongod.conf
Once above process starts running I also have to call mongodb/bin/mongo --eval rs.initiate()
Now the issue is I am starting mongod through supervisord I want to perform both of the above operation one after another. supervisord takes just 1 command to start the process which is first command. I have no other place to run the rs.initiate(). If I put both the command in shell script even then the control will be stuck with the first command itself.
Perhaps you could combine the commands into a single command. Ie,
mongod --config config/mongod.conf && sleep 5 && mongodb/bin/mongo --eval rs.initiate()
The sleep command assumes 5 seconds is enough for the mongod to come up and be available for an rs.initiate(). Given you are initiating a replica set I assume you have no data? If so, startup should be relatively quickly. Also if you are attempting to make a single node replica set you might want to consider...
rs.initiate (
{
_id: "somereplicasetname",
version: 1,
members:
[
{ _id: 0, host: "somehostname:27017" }
]
}
)
... so that you don't need to configure the initiated replicaset any further. The _id value (currently showing as somereplicasetname
) is expected to match the replica set name in the config file mongod.conf
and the somehostname
is expected to resolve to the current host.
By the way, I assume you recognize you only need to initialize a replica set once, not every time you start the mongod process..
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