Sorting a list in Descending numerical order and if number is the same, sort by Ascending alphabetical in Python

Question

I have 2 lists where I have to sort them both by descending order in the second list.

lst1 = ['Chris','Amanda','Boris','Charlie']
lst2 = [35,43,55,35]

I have sorted them by using

lst2, lst1 = (list(t) for t in zip(*sorted(zip(lst2, lst1), reverse=True)))

Because they are sorted using reverse=True my result is sorted by descending alphabetical order as well

This produces the result ['Boris', 'Amanda', 'Chris', 'Charlie'], [55, 43, 35, 35]

is there a way to produce the result ['Boris', 'Amanda', 'Charlie', 'Chris'], [55, 43, 35, 35] ?

Answer 1

Try this:

lst1 = ['Chris','Amanda','Boris','Charlie']
lst2 = [35,43,55,35]

lst1, lst2 = zip(*sorted(zip(lst1, lst2), key=lambda p: (-p[1], p[0])))

This produces:

>>> lst1
['Boris', 'Amanda', 'Charlie', 'Chris']
>>> lst2
[55, 43, 35, 35]
>>>