I have a file (say, file.txt) which looks like:
A,B,C,32
D,E,F,65
G,H,I,76
J,K,L,98
M,N,O,55
J,K,L,98
S,T,U,46
G,H,I,76
Now as there are 8 rows so I want to make 4 pairs. For the 1st time when it will take 2 rows, it will take the row with the highest 4th column value
and the 2nd row can be anyone from the remaining 7 rows
but self pairing is not allowed
. That means [(J,K,L,98),(J,K,L,98)]
can't be one pair. Suppose in the first iteration it has taken [(J,K,L,98),(S,T,U,46)]
as a pair, so in the next iteration there will be rest of the 6 rows participating.
Below is how I was trying:
from random import choice
file_name = 'file.txt'
fp = open(file_name)
val = []
for line in fp.readlines():
val.append(line.replace("\n","").split(","))
val = sorted(val, key=lambda x: x[-1], reverse=True)
item_list = []
for i in val:
i = list(map(str, i))
s = ','.join(i).replace("\n","")
item_list.append(s)
print(*item_list,sep='\n')
list1=[]
for i in val:
list1.append(i[-1])
print(list1)
p=max(list1)
print(max(list1))
final_list=[]
for i in val:
if(i[-1]==p):
final_list.append(i)
elif(i[-1]==choice(list1)):
final_list.append(i)
print(final_list)
Please help me out.
My interpretation of the problem is that you need to take a row from the file (table) with the highest numeric value in the 4th token. You then want to take another row at random and make that into a pair (a list of tuples). Key rule is that no pair can have equal tuples. I propose this:
from random import choice
# handles each row from the file creating an appropriately structured tuple
def mfunc(s):
t = s.strip().split(',')
t[-1] = int(t[-1])
return tuple(t)
# selects a random tuple from the given list ensuring that the selection cannot match the reference tuple
def gar(lst, ref=None):
rv = choice([e for e in lst if e != ref]) if ref else choice(lst)
lst.remove(rv)
return rv
with open('file.txt') as infile:
rows = sorted(list(map(mfunc, infile.readlines())), key=lambda x: x[-1])
output = []
t = rows[-1] # get row with highest value
rows.pop(-1) # then remove it
output.append([t, gar(rows, t)])
while len(rows) > 1:
a = gar(rows)
output.append([a, gar(rows, a)])
print(output)
Output (example):
[[('J', 'K', 'L', 98), ('M', 'N', 'O', 55)], [('S', 'T', 'U', 46), ('A', 'B', 'C', 32)], [('G', 'H', 'I', 76), ('D', 'E', 'F', 65)], [('G', 'H', 'I', 76), ('J', 'K', 'L', 98)]]
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