Currency Convert to Word in PHP INR way

Question

I am fatriedg an issue while converting the currency in the INR case. I want to make a function where if the amount does not have 'paisa' then in the last of the word will shows the 'only' word.

e.g 1: INR '100.23' will show: One Hundred and Two Three Paisa Only
e.g 2: INR '100' will show: One hundred Only

I have tried this code but I don't how I implement this same.

 function getIndianCurrency(float $number) { $decimal = round($number - ($no = floor($number)), 2) * 100; $hundred = null; $digits_length = strlen($no); $i = 0; $str = array(); $words = array(0 => '', 1 => 'one', 2 => 'two', 3 => 'three', 4 => 'four', 5 => 'five', 6 => 'six', 7 => 'seven', 8 => 'eight', 9 => 'nine', 10 => 'ten', 11 => 'eleven', 12 => 'twelve', 13 => 'thirteen', 14 => 'fourteen', 15 => 'fifteen', 16 => 'sixteen', 17 => 'seventeen', 18 => 'eighteen', 19 => 'nineteen', 20 => 'twenty', 30 => 'thirty', 40 => 'forty', 50 => 'fifty', 60 => 'sixty', 70 => 'seventy', 80 => 'eighty', 90 => 'ninety'); $digits = array('', 'hundred','thousand','lakh', 'crore'); while( $i < $digits_length ) { $divider = ($i == 2) ? 10 : 100; $number = floor($no % $divider); $no = floor($no / $divider); $i += $divider == 10 ? 1 : 2; if ($number) { $plural = (($counter = count($str)) && $number > 9) ? 's' : null; $hundred = ($counter == 1 && $str[0]) ? ' and ' : null; $str [] = ($number < 21) ? $words[$number].' '. $digits[$counter]. $plural.' '.$hundred:$words[floor($number / 10) * 10].' '.$words[$number % 10]. ' '.$digits[$counter].$plural.' '.$hundred; } else $str[] = null; } $rupees = implode('', array_reverse($str)); $paise = ''; if ($decimal) { $paise = ' and '; $decimal_length = strlen($decimal); if ($decimal_length == 2) { if ($decimal >= 20) { $dc = $decimal % 10; $td = $decimal - $dc; $ps = ($dc == 0) ? '' : '-' . $words[$dc]; $paise .= $words[$td] . $ps; } else { $paise .= $words[$decimal]; } } else { $paise .= $words[$decimal % 10]; } $paise .= ' paise only'; } return ($rupees ? $rupees . 'rupees' : '-') . $paise ; }

Answer 1

Here You go. try this.

<?php
function getIndianCurrency(float $number)
{
    $decimal = round($number - ($no = floor($number)), 2) * 100;
    $hundred = null;
    $digits_length = strlen($no);
    $i = 0;
    $str = array();
    $words = array(0 => '', 1 => 'one', 2 => 'two',
        3 => 'three', 4 => 'four', 5 => 'five', 6 => 'six',
        7 => 'seven', 8 => 'eight', 9 => 'nine',
        10 => 'ten', 11 => 'eleven', 12 => 'twelve',
        13 => 'thirteen', 14 => 'fourteen', 15 => 'fifteen',
        16 => 'sixteen', 17 => 'seventeen', 18 => 'eighteen',
        19 => 'nineteen', 20 => 'twenty', 30 => 'thirty',
        40 => 'forty', 50 => 'fifty', 60 => 'sixty',
        70 => 'seventy', 80 => 'eighty', 90 => 'ninety');
    $digits = array('', 'hundred','thousand','lakh', 'crore');
    while( $i < $digits_length ) {
        $divider = ($i == 2) ? 10 : 100;
        $number = floor($no % $divider);
        $no = floor($no / $divider);
        $i += $divider == 10 ? 1 : 2;
        if ($number) {
            $plural = (($counter = count($str)) && $number > 9) ? 's' : null;
            $hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
            $str [] = ($number < 21) ? $words[$number].' '. $digits[$counter]. $plural.' '.$hundred:$words[floor($number / 10) * 10].' '.$words[$number % 10]. ' '.$digits[$counter].$plural.' '.$hundred;
        } else $str[] = null;
    }
    $Rupees = implode('', array_reverse($str));
    $paise = ($decimal > 0) ? "and " . ($words[$decimal / 10] . " " . $words[$decimal % 10]) . 'Paise' : '';
    return ($Rupees ? $Rupees . '' : '') . $paise . ' Only';
}



echo getIndianCurrency(100.20);