geom_tile fill tile based on logical values (0 and 1) with different fill colors by group

Question

I have a dataframe like this:

df <- data.frame("Name" = rep(c("Aa", "Ab", "Ac", "Ba", "Ca", "Cb"), 3),
             "Level" = c(rep("High",6), rep("Medium",6), rep("Low",6)),
             "plot.fill" = c(0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1),
             "Group" = rep(c("A", "A", "A", "B", "C", "C"), 3))

I'm trying to plot this data using geom_tile . I figured out how to make the tile filled or not using the plot.fill parameter:

ggplot(df, aes(x=Name, y=Level, fill = plot.fill == 1)) +
  geom_tile() + scale_fill_manual(values = c('FALSE'="white", 'TRUE'="blue"))

But I also want to fill the tile with different colors based on Group . I tried this but now it fills all tiles regardless of plot.fill .

ggplot(df, aes(x=Name, y=Level, fill = Group)) +
  geom_tile() + scale_fill_manual(values = c("blue","red","yellow"))  

I also tried adding aes(fill=Group) in the geom_tile arguemnt, but it gives me an error ( mapping must be created by aes() ). How should I combine what each code is doing to fill the tiles in different colors by Group only if the plot.fill values equal 1 ?

Answer 1

You could use the alpha scale, identity-mapped to plot.fill , to indicate presence / absence. This allows you to use the fill aesthetic to indicate Group :

ggplot(df, aes(Name, Level, fill = Group, alpha = plot.fill)) +
  geom_tile(color = "black") +
  scale_alpha_identity() +
  scale_fill_brewer(palette = "Set1") +
  coord_equal() +
  theme_minimal(base_size = 16) +
  theme(panel.grid = element_blank())